Hi Dipankar,
We are differentiating with respect to x,
So,
If there was x,
d(x^2)/dx = 2 x^2-1 dx/dx = 2x
But since here it is p^n
We write
d(p^n)/dx = np^n-1 d(p)/dx
Written on Feb. 15, 2017, 7:02 p.m.
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Answer of this question
How p^n =np^n-1 p why is this extra p added
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